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Á¦ ¸ñ : Â÷¿ø°ú ´ÜÀ§(Dimension and Unit)
Â÷¿ø°ú ´ÜÀ§´Â °£È¤ È¥µ·À» ºÒ·Á ¿À´Â ¹ÐÁ¢ÇÑ °ü°è·Î ¹°ÁúÀûÀÎ ±âÁØÀ» Áú·®(M : Mass), ±æÀÌ(L: Length), ½Ã°£ (T: Time), ¿Âµµ(K: Kelvin)¸¦ ±âº»Â÷¿ø(Basic Dimension)À̶ó°í Á¤ÀÇÇÑ´Ù. ¶ÇÇÑ, ÀÌ·¯ÇÑ ±âº» Â÷¿ø¿¡¼­ À¯µµµÈ Â÷¿øÀ» À¯µµÂ÷¿øÀ̶ó°í ÇÑ´Ù.(¼Óµµ, °¡¼Óµµ µîµî)
¿©±â¿¡ »ç¿ëµÇ´Â ´ÜÀ§(Unit)´Â ÀÌ·¯ÇÑ ¹°¸®ÀûÀÎ Â÷¿øÀÇ Å©±â¸¦ ³ªÅ¸³»±â À§ÇØ »ç¿ëÇÏ´Â °ÍÀ» ´ÜÀ§¶ó°í Çϸç, Á¾·ù¿¡´Â Àý´ë´ÜÀ§¿Í ÈûÀÇ ´ÜÀ§(F,L,T)¸¦ »ç¿ëÇϴµ¥, Àý´ë´ÜÀ§¿¡´Â M,K,S ´ÜÀ§¿Í C,G,S¸¦ »ç¿ëÇϸç, ÈûÀÇ ´ÜÀ§¿¡´Â SI ´ÜÀ§(N)¿Í °øÇдÜÀ§(Kgf)¸¦ »ç¿ëÇÑ´Ù.
ÇÏÁö¸¸, °£È¤, ¿ì¸®´Â ´ÜÀ§ »ç¿ë¿¡ ÀÖ¾î Àý´ë ´ÜÀ§¿Í Áß·Â ´ÜÀ§ÀÇ »óÈ£°£¿¡ È¥µ·À» °¡Áö°í ÀÖÀ¸¸ç, Áß·®=Áú·®*Á߷°¡¼Óµµ °ø½Ä¿¡¼­ Áú·®Àº Áß·®/Á߷°¡¼Óµµ·Î ´ÜÀ§¸¦ ȯ»êÇÒ °æ¿ì Áß·®(Èû)ÀÇ ´ÜÀ§¿Í Áú·® °ü°è¿¡¼­ Âø°¢ÇÏ´Â °æ¿ì°¡ ´õ·¯ ÀÖ¾î ¾Æ·¡¿Í °°ÀÌ °³³äÀ» Á¤¸®ÇÏ°íÀÚ ÇÑ´Ù.

Sometimes, We are confused to find the matter which used unit is correct after or before transforming the physical analysis in Mechanical calculation. For example, Especially, between an absolute unit and Force unit, either consists of combined unit or transformed unit from which to final mechanical calculation.
Generally, we do know that force(F) is equal to Mass by Acceleration, ie F=m*a as per Newton"s 2nd law, we can put "g" (Gravity acceleration) as of acceleration velocity here, in this case, can we say that 70Kg is equal to 70Kgf, Obviously 70Kg is Mass unit, on the contrary, 70Kgf is of Force unit using formula of W(Weight)=m(Mass)*g(Gravity acceleration), the answer this question is correct, however, we can think about that m(Mass) can be calculated by W(Weight) divided by "g"(Gravity acceleration), 9.8 m/s^2 simply, This would be really to make us confused without corrective comprehension of relative concept between Unit and Force.
Corrective answer is 70Kgf of weight that is equal to 70Kg of Mass because the different thing is only unit but 70kgf is of force(70Kg of mass to Gravity acceleration) and then divided by Gravity acceleration(9.8 m/^2), the result of this calculation will be of 70kg (70Kg * 9.8 m/s^2 / 9.8 m/s^2).

For more explanation, in the density of Air, we can put either about 1.2 kgf/m^3 or 1.2kg/m^3, In this way, for water, either 1,000kg/m^3 or 1,000kgf/m^3, the first one is of mass unit, second one is of force unit, the correct figure is will not be changed as same 1,000 regardless of used unit and, we can use either 1,000kg or 1,000kgf because all of the mass over affected by same Gravity acceleration (9.8m/s^2) or we can put simply Gravity acceleration.

In this regard, we can use either mass unit or force unit as same as mechanical calculation, ie we can express that my weight is of 70kgf or 70kg regardless of corrective unit usage.
FInally, we can do say 70kgf=70kg as refering to numerical formula, F=mg=70kgf, m=F/g=70kgf/9.8m/s^2, here, f=9.8m/s^2
70kg*9.8m/s^2 / 9.8m/s^2 = 70kg so hereby, when we induce force unit by Newton (N), for 70kgf will be equal to 70kg*9.8m/s^2 = 686N (N=1kg*1m/s^2) and how about
70kg of mass, thereby F=mg, 70kg * 9.8m/s^2 = 686N
"The End"

2015.06.15.
Ryu ChangMyong / P.E
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Â÷¿ø°ú ´ÜÀ§(Dimension and Un...

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2015-06-15

7971